Irfan Rahadi Kurninato

السلام عليكم Irfan Rahadi Kurnianto - 1706036255

4 September 2019

---

Mengapa kita harus belajar kalkulus?
kalkulus adalah mata kuliah dasar teknik. Mata kuliah kalkulus sangat berguna untuk membentuk logika agar mudah dalam belajar suatu hal lain

Tugas 1

11 September 2019

---

Bit Komputer
Program Catur

coding bukan pelajaran anak fasilkom/elektro
belajar python
praktek programing
dasar2 programing + pyhton
programnya irfan t2 dikelas

18 September 2019

---

Tugas irfan 18 sep 19

25 September 2019

---

Tugas irfan 25 sep 19
catatan irfan 25 sep 19

Kuis 16 Oktober 2019

---

program runge kutta

https://pastebin.com/GxfenTa3
# dibuat oleh irfan rahadi 1706036255

def TurunanY(x, y): #Fungsi Turunan Y
return ((x**2 - 4*y))   
xawal = 0 #boundary condition x awal soal
yinit = 1 #boundary condition y awal soal
x = 0.03  #nilai x yang ditanya
h = 0.01  #delta yang digunakan
angka = (int)((x - xawal)/h) #menghitung jumlah increment yg diperlukan  
for i in range(1, angka + 1):
k1 = h * TurunanY(xawal, yinit) #rumus runge kutta
k2 = h * TurunanY(xawal + 0.5 * h, yinit + 0.5 * k1)
k3 = h * TurunanY(xawal + 0.5 * h, yinit + 0.5 * k2)
k4 = h * TurunanY(xawal + h, yinit + k3)
yinit = yinit + (1.0 / 6.0)*(k1 + 2 * k2 + 2 * k3 + k4) #menjumlahkan nilai k1,k2,k3,k4 ke y' yang baru dan membaginya  
xawal = xawal + h #menambahkan xawal besarkan delta h
print(yinit)

 PROGRAM GAUSS
from numpy import linalg 
import numpy as np
a= np.array ([[0,0,2,1,2] ,[0,1,0,2,-1], [1,2,0,-2,1], [0,0,0,-1,1], [0,1,-1,1,-1]])
b= np.array ([[1], [1], [-4], [-2], [-1]])
c= np.array ([[0,0,2,1,2,1] ,[0,1,0,2,-1,1], [1,2,0,-2,1,-4], [0,0,0,-1,1,-2], [0,1,-1,1,-1,-1]])
print ("Matrix a " , a)
print ("Matrix b ", b)
print ("Matrixnya adalah:" , c)
matsolve = linalg.solve (a,c)
x1 = int(matsolve[0])
x2 = int(matsolve[1])
x3 = int(matsolve[2])
x4 = int(matsolve[3])
x5 = int(matsolve[4])
hasil= (x1, x2, x3, x4, x5)
print ("Hasil nilai x1,x2,x3,x4,x5 :")
print (hasil)

UTS 23 oktober

---

Video Muhasabah

3 A
# Cara 1
m1 = eval(input("Massa Benda 1 ? ")) #menginput m1
m2 = eval(input("Massa Benda 2 ? "))#menginput m2
m3 = eval(input("Massa Benda 3 ? ")) #meninput m3
m4 = eval(input("Massa Benda 4 ? "))
g = eval(input("Gravitasi ? "))         #input g
sinusa = ((m1+m2+m3)/m4)#hitung sin theta
T1 = m1*sinusa*g #hitung T1
T2 = m2*sinusa*g + T1 #hitung T2
T3 = m3*sinusa*g + T2 #hitung T3
print("T1", T1)
print("T2",T2)
print("T3", T3)
print("Sin theta = ", sinusa,"")


#Cara 2
m1 = eval(input("Massa Benda 1 ? "))
m2 = eval(input("Massa Benda 2 ? "))
m3 = eval(input("Massa Benda 3 ? "))
m4 = eval(input("Massa Benda 4 ? "))
g = eval(input("Gravitasi ? "))         
sinusa = ((m1+m2+m3)/m4)
Matrex=[[1,0,0,m1*sinusa*g],[1,1,0,(2*m1+m2)*sinusa*g],[2,1,1,((2*(2*m1+m2))+m3)*sinusa*g]]      #Matrix yg mau di gauss
def PrintMatrix(Matrix): #untuk print
    for i in range(len(Matrix)):
        for j in range(len(Matrix[i])):
            print(Matrix[i][j],end="\t")
        print()
def MultiplyRow(Row,Scalar): #untuk kali
    for i in range(len(Row)):
        Row[i]=Row[i]*Scalar
def AddRow(Matrix,RowNR1,RowNR2,multi=1): #untuk tambah
    for i in range(len(Matrix[RowNR2])):
        Matrix[RowNR2][i]+=Matrix[RowNR1][i]*multi
def SwitchRow(Matrix,RowNR1,RowNR2): #untuk tukar
    bufrow=Matrix[RowNR1]
    Matrix[RowNR1]=Matrix[RowNR2]
    Matrix[RowNR2]=bufrow
    return 0
def ZeroRowsBelow(Matrix,RowNR,CollumnNR): #untuk menghindari eror 0
    for i in range(len(Matrix)-RowNR-1):
        if not(Matrix[RowNR][CollumnNR]==0):
            AddRow(Matrix,RowNR,i+1+RowNR,-float(Matrix[i+1+RowNR][CollumnNR])/Matrix[RowNR][CollumnNR])
            #print(i)
def SolveMatrix(Matrix):     #untuk mensolve
    #Bring To Row-Echelon Form
    for i in range(len(Matrex)):
        ZeroRowsBelow(Matrex,i,i)
   #Make Row-Echelon 1
    for i in range(len(Matrex)):
       if not(Matrex[i][i]==0):
            MultiplyRow(Matrex[i],1./Matrex[i][i])
    #diulang lagi
    for i in range(len(Matrex)):
        for j in range(i):
            if not(Matrex[i][i]==0):
                AddRow(Matrex,i,j,-float(Matrex[j][i])/Matrex[i][i])
def IsRRowEchelon(Matrix): #cek selsai
    for i in range(len(Matrix)):
        pos=[1,0]
        if not(Matrix[i][i] in pos):
            return 0
    return 1
def CheckForEqualRows(Matrix):#cek nilai
    newlist=[]
    for i in Matrix:
        if i not in newlist:
            newlist.append(i)
    return newlist   
MatrixNew=[]
for j in range(len(Matrex)):
    RowNew=[]
    for i in range(len(Matrex[j])):
        RowNew.append(Matrex[j][i])
    MatrixNew.append(RowNew)
Matrex=MatrixNew
PrintMatrix(Matrex)
print()
while True:
    SolveMatrix(Matrex)
    Matrex=CheckForEqualRows(Matrex)
    if IsRRowEchelon(Matrex):
        break
PrintMatrix(Matrex)#print matrix
print("")
print("Solusinya")
print("T1 = ",Matrex[0][3])
print("T2 = ",Matrex[1][3])
print("T3 = ",Matrex[2][3])
print("Sin Theta = ",Matrex[0][3]/(m1*g))

3 B
cara 1
cd=eval(input("drag coefficient: ")) #input coef drag
Vawal=0 #kondisi diam
m=eval(input("mass (kg): ")) #massa
a=eval(input("acceleration (m/s^2): ")) #perc
Vakhir=eval(input("top speed (m/s): ")) #vtop
fdrag=(cd*Vakhir**(3/2))/m #gayagesek
Ftotal=a-fdrag
Atotal = Ftotal #dibagi m
t=(Vakhir-Vawal)/Atotal #hitung waktu
print("Waktu untuk mencapai Vakhir: ",t, "detik")
Cara 2
 def TurunanKec(perc, vakir): #Fungsi 
  return (percepatan - ((cd*vakir**(3/2))/m)) 
cd=eval(input("drag coefficient: ")) #input coef drag
Vawal=0 
#kondisi diam 
m=eval(input("mass (kg): ")) #massa 
percepatan=eval(input("acceleration (m/s^2): ")) 
#perc 
Vakhir=eval(input("top speed (m/s): ")) 
#vtop 
xawal = 0 #boundary condition x awal soal 
yinit = 0 #boundary condition y awal soal 
x = Vakhir  #nilai x yang ditanya 
h = 1  #delta yang digunakan 
angka = (int)((x - xawal)/h) #menghitung jumlah increment yg diperlukan 
for i in range(1, angka + 1): 
  k1 = h * TurunanKec(xawal, yinit) #rumus runge kutta 
  k2 = h * TurunanKec(xawal + 0.5 * h, yinit + 0.5 * k1) 
  k3 = h * TurunanKec(xawal + 0.5 * h, yinit + 0.5 * k2) 
  k4 = h * TurunanKec(xawal + h, yinit + k3) 
  yinit = yinit + (1 / 6.0)*(k1 + 2 * k2 + 2 * k3 + k4) #menjumlahkan nilai k1,k2,k3,k4 ke y' yang baru dan membaginya 
  xawal = xawal + h 
  #menambahkan xawal besarkan delta h 
print("waktu yang dibutuhkan", yinit,"sekon")

Tugas 30 Oktober

---

 def TurunanKec(perc, vakir): #Fungsi 
   return (9.8*sina-(1/2)*(1/m)*(cd)**(3/2)-miu*9.8) 
cd=eval(input("drag coefficient: ")) #input coef drag
miu = eval(input("koef gesek: "))
Vawal=0  #kondisi diam 
sina = 0.5
m=eval(input("mass (kg): ")) #massa 
percepatan=eval(input("acceleration (m/s^2): ")) 
 #perc 
Vakhir=eval(input("top speed (m/s): ")) 
#vtop 
xawal = 0 #boundary condition x awal soal 
yinit = 0 #boundary condition y awal soal 
x = Vakhir  #nilai x yang ditanya 
h = 1  #delta yang digunakan 
angka = (int)((x - xawal)/h) #menghitung jumlah increment yg diperlukan 
for i in range(1, angka + 1): 
  k1 = h * TurunanKec(xawal, yinit) #rumus runge kutta 
  k2 = h * TurunanKec(xawal + 0.5 * h, yinit + 0.5 * k1) 
  k3 = h * TurunanKec(xawal + 0.5 * h, yinit + 0.5 * k2) 
  k4 = h * TurunanKec(xawal + h, yinit + k3) 
  yinit = yinit + (1 / 6.0)*(k1 + 2 * k2 + 2 * k3 + k4) #menjumlahkan nilai k1,k2,k3,k4 ke y' yang baru dan membaginya 
  xawal = xawal + h 
  #menambahkan xawal besarkan delta h 
print("waktu yang dibutuhkan", yinit,"sekon")

Sort by date Sort by score

Enable comment auto-refresher

Add your comment

ccitonlinewiki welcomes all comments. If you do not want to be anonymous, register or log in. It is free.