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Saya Rawhul Ihsan Setyoko dengan NPM 2106639371, mahasiswa Teknik Perkapalan 2021, saya lahir di jakarta 13 Agustus 2003
 
Saya Rawhul Ihsan Setyoko dengan NPM 2106639371, mahasiswa Teknik Perkapalan 2021, saya lahir di jakarta 13 Agustus 2003
  
 +
== My Concious Effort on Numerical Method Learning and Its Application in Hydrogen Storage Design ==
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=
  
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== Resume 26/05/2023 ==
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=
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pada hari ini saya belajar untuk bagaimana kita saling mengenal dengan bapak Ahmad Indra, pak DAI berharap bahwa mahasiswa memanfaatkan waktu untuk berinteraksi dengan dosen,belajar mandiri juga penting dan tidak hanya mengandalkan belajar di kelas, pak DAI menjelaskan bagaimana individual study case yang harus dikerjakan, belajar apapun harus melihat realitas, conciesness adalah kondisi dimana kesadaran tidak hanya fisik saja,
 
  
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pada hari ini saya juga belajar bahwa sebenarnya aspek consciousness merupakan salah satu yang terpenting dalam kehidupan kita, bagaimana kita menggunakan otak kita dalam memproses hal - hal yang terjadi di sekitar kita, dan bagaimana kita menggunakan otak untuk merepresentasikan dunia yang sekarang kita lihat, dimana kesimpulan yang dapat saya ambil adalah bahwa setiap permasalahan pasti membutuhkan aspek conscious untuk menyelesaikannya, bahkan bagaimana kita sebagai manusia mengkonstruksi dunia di sekeliling kita pasti membutuhkan conscious dan kepercayaan bahwa dunia tersebut ada, dapat dilihat pada masalah dimana kita bisa mendapatkan solusinya, namun semua solusi tidak bisa dibuktikan secara exact apakah solusi tersebut benar atau tidak, karena jika bisa dibuktikan maka tidak ada ruang tersisa untuk kepercayaan (faith).
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== Design & Optimization of Pressurized Hydrogen Storage ==
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'''Study Case'''
  
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== Design & Optimization of Pressurized Hydrogen Storage ==
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Design and Optimization
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of Prezzurized Hydrogen Storage
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Capacity : 1 L
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Pressure : 8 bar
  
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Cost should not exceed Rp. 500000
  
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the study case is for determine the most efficient design of pressurized hydrogen storage at minimal cost, this are some step recommended by me based on my research
 
  
  
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in some research, the best material for optimazing the performance of the storage is to use layers, layers are the combine system of two or more material to maximise the effect of both material, in this case we use 2 material :
 
in some research, the best material for optimazing the performance of the storage is to use layers, layers are the combine system of two or more material to maximise the effect of both material, in this case we use 2 material :
 +
  
 
1. GFRP (Glass Fiber Reinforced Plastic)
 
1. GFRP (Glass Fiber Reinforced Plastic)
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 +
2. Alumunium
  
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2. Alumunium
 
  
  
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Life cycle assessment method for determine the tube life cycle from the storage material until it’s not being used anymore, the main factor from this method is knowing whether this storage are toxic to the nature around. the step of doing this assessment are :
 
Life cycle assessment method for determine the tube life cycle from the storage material until it’s not being used anymore, the main factor from this method is knowing whether this storage are toxic to the nature around. the step of doing this assessment are :
 +
  
 
1. Objective and scope analysis
 
1. Objective and scope analysis
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4. Result Interpretation
 
4. Result Interpretation
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 +
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== Thickness ==
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 +
using two different layers material based on research, Alumunium and GFRP, we can generate the codes
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 +
    import math
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    def calculate_optimal_thickness(volume, pressure, tensile_strength_aluminum, tensile_strength_gfrp):
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    # Constants
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    safety_factor = 4  # Safety factor for design
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 +
    # Calculation
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    total_thickness = (volume * pressure) / (2 * math.pi * (tensile_strength_aluminum / safety_factor + tensile_strength_gfrp / safety_factor))
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    thickness_aluminum = total_thickness * (tensile_strength_aluminum / safety_factor) / (tensile_strength_aluminum / safety_factor + tensile_strength_gfrp / safety_factor)
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    thickness_gfrp = total_thickness - thickness_aluminum
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    return thickness_aluminum, thickness_gfrp
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 +
    # Input values
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    volume = 1  # Volume in liters
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    pressure = 8 * math.pow(10, 5)  # Pressure in Pascals (1 bar = 10^5 Pascals)
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 +
    # Convert volume to cubic meters
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    volume = volume / 1000
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    # Convert pressure to Pascals
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    pressure = pressure * math.pow(10, 5)
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 +
    # Material properties
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    tensile_strength_aluminum = 276 * math.pow(10, 6)  # Tensile strength of aluminum in Pascals
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    tensile_strength_gfrp = 500 * math.pow(10, 6)  # Tensile strength of glass fiber reinforced plastic in Pascals
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 +
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    # Calculate optimal thickness
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    aluminum_thickness, gfrp_thickness = calculate_optimal_thickness(volume, pressure, tensile_strength_aluminum, tensile_strength_gfrp)
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 +
    # Output
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    print(f"The optimal thickness for a hydrogen tube with a {volume} m^3 capacity and {pressure} Pa pressure is split between aluminum thickness: {aluminum_thickness}
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    meters and GFRP thickness: {gfrp_thickness} meters.")
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 +
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The optimal thickness for a hydrogen tube with a 1 L capacity and 0.8 mPa pressure is split between '''aluminum thickness: 3 mm GFRP thickness: 4 mm'''
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 +
== Height and Diameter ==
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 +
next we determine the height and diameter of the tube
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 +
    import math
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 +
    def calculate_optimal_dimensions(volume, pressure):
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    # Constants
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    safety_factor = 4  # Safety factor for design
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 +
    # Calculation
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    radius = math.sqrt(volume / (math.pi * math.sqrt(2)))  # Optimal radius
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    height = (2 * pressure * safety_factor) / (radius * math.sqrt(2))  # Optimal height
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    diameter = 2 * radius  # Optimal diameter
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    return height, diameter
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 +
    # Input values
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    volume = 1  # Volume in liters
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    pressure = 0.8 * math.pow(10, 6)  # Pressure in Pascals (1 MPa = 10^6 Pascals)
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 +
    # Convert volume to cubic meters
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    volume = volume / 1000
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    # Calculate optimal height and diameter
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    optimal_height, optimal_diameter = calculate_optimal_dimensions(volume, pressure)
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 +
    # Output
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    print(f"The optimal dimensions for a hydrogen tube with a {volume} m^3 capacity and {pressure} Pa pressure are height: {optimal_height} meters and diameter:
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    {optimal_diameter} meters.")
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'''The optimal dimensions for a hydrogen tube with a 1 L capacity and 0.8 mPa pressure are height: 0.305 meters and diameter: 0.12 meters.'''
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 +
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== Surface Area ==
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    import math
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 +
    def calculate_surface_area(height, diameter):
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    radius = diameter / 2
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    base_area = math.pi * radius**2
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    lateral_area = 2 * math.pi * radius * height
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    surface_area = 2 * base_area + lateral_area
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    return surface_area
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    def calculate_cross_sectional_area(diameter):
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    radius = diameter / 2
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    cross_sectional_area = math.pi * radius**2
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    return cross_sectional_area
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    # Example usage
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    height = 30  # in cm
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    diameter = 12  # in cm
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    surface_area = calculate_surface_area(height, diameter)
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    cross_sectional_area = calculate_cross_sectional_area(diameter)
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    print("Surface Area:", surface_area, "cm^2")
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    print("Cross-sectional Area:", cross_sectional_area, "cm^2")
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'''Surface Area: 1357.1680263507906 cm^2
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 +
Cross-sectional Area: 113.09733552923255 cm^2'''
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== Cost ==
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[[File:Gfrp Prices.jpg]]
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 +
after determining the Surface Area, we can determine the cost for all material that we used, Glass Fiber Reinforced Plastic and Aluminium, when the calculation is done, we get '''$7.12 or Rp105.848 for GFRP and Rp278.000 for Aluminium, so the total cost is Rp383.484'''

Latest revision as of 18:10, 19 April 2024

INTRODUCTION Saya Rawhul Ihsan Setyoko dengan NPM 2106639371, mahasiswa Teknik Perkapalan 2021, saya lahir di jakarta 13 Agustus 2003

My Concious Effort on Numerical Method Learning and Its Application in Hydrogen Storage Design

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Design & Optimization of Pressurized Hydrogen Storage

Study Case

Design and Optimization of Prezzurized Hydrogen Storage


Capacity : 1 L

Pressure : 8 bar

Cost should not exceed Rp. 500000


Design Optimization and Material Choosing

in some research, the best material for optimazing the performance of the storage is to use layers, layers are the combine system of two or more material to maximise the effect of both material, in this case we use 2 material :


1. GFRP (Glass Fiber Reinforced Plastic)

2. Alumunium


To maximize the performance of the storage, we can use 2 layer of material, those material are metallic and composite polymeric layers thicknesses, number of composite layers and winding angle of filament-wound composite, were studied. Using Numerical Method Finite Element Analysis on a parametric study including 64 cases, shooting minimum tank weight and cost was performed. Using different thickness of composite polymeric layers is significant the same over all composite layers thickness Optimal design was found to be 8 mm thickness of Aluminum liner and one composite layer of high toughness GFRP material with thickness of 6 mm at angle 65°


Using Sorption - Based Storage

The timing between supply and energy demand cause calls for reliable storage system. In this current years, energy storage system become further significant with the widespread implementation of renewable energy. Hydrogen is being a renewable energy with the most demands past the current years, that makes hydrogen storage keep being upgraded to provide the most efficient storage at minimum price, with the research I did from reading many sources, that one journal says that hydrogen storage with sorption based storage system exibit huge potential due to a high energy density. An average temperature lift of 25 °C, energy density of 40 kWh/m3 , and energy efficiency of 73% were obtained.


Do the Life Cycle Assessment method

Life cycle assessment method for determine the tube life cycle from the storage material until it’s not being used anymore, the main factor from this method is knowing whether this storage are toxic to the nature around. the step of doing this assessment are :


1. Objective and scope analysis

Ensure that when the product has passed the limit of use / old age, then the product will be treated in such a way that it does not damage and disturb nature.


2. Inventory Analysis

environmental influences in each stage of the analysis


3. Environmental Impact Analysis

material impact on the environment


4. Result Interpretation


Thickness

using two different layers material based on research, Alumunium and GFRP, we can generate the codes 

   import math
   def calculate_optimal_thickness(volume, pressure, tensile_strength_aluminum, tensile_strength_gfrp):
   # Constants
   safety_factor = 4  # Safety factor for design

   # Calculation
   total_thickness = (volume * pressure) / (2 * math.pi * (tensile_strength_aluminum / safety_factor + tensile_strength_gfrp / safety_factor))
   thickness_aluminum = total_thickness * (tensile_strength_aluminum / safety_factor) / (tensile_strength_aluminum / safety_factor + tensile_strength_gfrp / safety_factor)
   thickness_gfrp = total_thickness - thickness_aluminum
   return thickness_aluminum, thickness_gfrp

   # Input values
   volume = 1  # Volume in liters
   pressure = 8 * math.pow(10, 5)  # Pressure in Pascals (1 bar = 10^5 Pascals)

   # Convert volume to cubic meters
   volume = volume / 1000

   # Convert pressure to Pascals
   pressure = pressure * math.pow(10, 5)

   # Material properties
   tensile_strength_aluminum = 276 * math.pow(10, 6)  # Tensile strength of aluminum in Pascals
   tensile_strength_gfrp = 500 * math.pow(10, 6)  # Tensile strength of glass fiber reinforced plastic in Pascals



   # Calculate optimal thickness
   aluminum_thickness, gfrp_thickness = calculate_optimal_thickness(volume, pressure, tensile_strength_aluminum, tensile_strength_gfrp)

   # Output
   print(f"The optimal thickness for a hydrogen tube with a {volume} m^3 capacity and {pressure} Pa pressure is split between aluminum thickness: {aluminum_thickness} 
   meters and GFRP thickness: {gfrp_thickness} meters.")


The optimal thickness for a hydrogen tube with a 1 L capacity and 0.8 mPa pressure is split between aluminum thickness: 3 mm GFRP thickness: 4 mm

Height and Diameter

next we determine the height and diameter of the tube 

   import math

   def calculate_optimal_dimensions(volume, pressure):
   # Constants
   safety_factor = 4  # Safety factor for design

   # Calculation
   radius = math.sqrt(volume / (math.pi * math.sqrt(2)))  # Optimal radius
   height = (2 * pressure * safety_factor) / (radius * math.sqrt(2))  # Optimal height
   diameter = 2 * radius  # Optimal diameter
   return height, diameter

   # Input values
   volume = 1  # Volume in liters
   pressure = 0.8 * math.pow(10, 6)  # Pressure in Pascals (1 MPa = 10^6 Pascals)

   # Convert volume to cubic meters
   volume = volume / 1000

   # Calculate optimal height and diameter
   optimal_height, optimal_diameter = calculate_optimal_dimensions(volume, pressure)

   # Output
   print(f"The optimal dimensions for a hydrogen tube with a {volume} m^3 capacity and {pressure} Pa pressure are height: {optimal_height} meters and diameter: 
   {optimal_diameter} meters.")

The optimal dimensions for a hydrogen tube with a 1 L capacity and 0.8 mPa pressure are height: 0.305 meters and diameter: 0.12 meters.


Surface Area

   import math

   def calculate_surface_area(height, diameter):
   radius = diameter / 2
   base_area = math.pi * radius**2
   lateral_area = 2 * math.pi * radius * height
   surface_area = 2 * base_area + lateral_area
   return surface_area

   def calculate_cross_sectional_area(diameter):
   radius = diameter / 2
   cross_sectional_area = math.pi * radius**2
   return cross_sectional_area

   # Example usage
   height = 30  # in cm
   diameter = 12  # in cm

   surface_area = calculate_surface_area(height, diameter)
   cross_sectional_area = calculate_cross_sectional_area(diameter)

   print("Surface Area:", surface_area, "cm^2")
   print("Cross-sectional Area:", cross_sectional_area, "cm^2")

Surface Area: 1357.1680263507906 cm^2

Cross-sectional Area: 113.09733552923255 cm^2


Cost

Gfrp Prices.jpg

after determining the Surface Area, we can determine the cost for all material that we used, Glass Fiber Reinforced Plastic and Aluminium, when the calculation is done, we get $7.12 or Rp105.848 for GFRP and Rp278.000 for Aluminium, so the total cost is Rp383.484

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