Difference between revisions of "Nadhif Rizki Priambodo"
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Mengikuti lomba kompetisi mobil hemat energi dan shell eco marathon tahun 2018-2020 | Mengikuti lomba kompetisi mobil hemat energi dan shell eco marathon tahun 2018-2020 | ||
| + | |||
| + | Hasil QUIZ | ||
| + | |||
| + | coding | ||
| + | print ("QUIZ nadhif rizki p - 1706026140") | ||
| + | A = np.array([[1, 2, 0, -2, 0], [0, 1, 0, 2, -1], [0, 1, -1, 1, -1], [0, 0, 0, -1, 1], [0, 0, 2, 1, 2]], float) | ||
| + | B=np.array([-4, 1, -1, -2, 1],float) | ||
| + | |||
| + | n=len(A) | ||
| + | |||
| + | # menggunakan gauss elimination | ||
| + | |||
| + | for k in range (0,n-1): | ||
| + | for i in range (k+1, n): | ||
| + | if A[i,k] ! = 0 | ||
| + | lam= A[i,k]/A[k,k] | ||
| + | A[i,k:n]= A[i,k:n]-(A[k,k:n]*lam) | ||
| + | B[i]=B[i]-(B[k]*lam) | ||
| + | |||
| + | print ("matrix A:", "\n", A) | ||
| + | |||
| + | x=np.zeros( n,float) | ||
| + | for m in range ( n-1, -1, -1)P: | ||
| + | x[m]=(B[m]-np.dot(A[m, m+1:n], x[m+1:n]))/A[m,m] | ||
| + | print ('nilai x', m+1, '=', x[m]) | ||
| + | |||
| + | SCREENSHOT HASIL | ||
Revision as of 15:10, 14 October 2019
[Nama : Nadhif rizki priambodo]
[Semester : 5]
[Npm : 1706026140]
Mengikuti lomba kompetisi mobil hemat energi dan shell eco marathon tahun 2018-2020
Hasil QUIZ
coding print ("QUIZ nadhif rizki p - 1706026140") A = np.array([[1, 2, 0, -2, 0], [0, 1, 0, 2, -1], [0, 1, -1, 1, -1], [0, 0, 0, -1, 1], [0, 0, 2, 1, 2]], float) B=np.array([-4, 1, -1, -2, 1],float)
n=len(A)
- menggunakan gauss elimination
for k in range (0,n-1):
for i in range (k+1, n):
if A[i,k] ! = 0
lam= A[i,k]/A[k,k]
A[i,k:n]= A[i,k:n]-(A[k,k:n]*lam)
B[i]=B[i]-(B[k]*lam)
print ("matrix A:", "\n", A)
x=np.zeros( n,float) for m in range ( n-1, -1, -1)P:
x[m]=(B[m]-np.dot(A[m, m+1:n], x[m+1:n]))/A[m,m]
print ('nilai x', m+1, '=', x[m])
SCREENSHOT HASIL
