Difference between revisions of "Mohammad Varian"
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[[File:testt.PNG]] | [[File:testt.PNG]] | ||
| + | ==Tugas 03== | ||
| + | |||
| + | Menggunakan persamaan matriks untuk eliminasi Gauss. | ||
| + | |||
| + | <div border-style: inset;"> | ||
| + | 6x<sub>1</sub> + 4x<sub>2</sub> = 50 | ||
| + | 2x<sub>1</sub> + x<sub>3</sub> + 4x<sub>4</sub> = 50 | ||
| + | 7x<sub>2</sub> + 3x<sub>3</sub> + 4x<sub>4</sub> = 50 | ||
| + | 4x<sub>1</sub> + 4x<sub>3</sub> = 50 | ||
| + | |||
| + | Didapat hasil matrix: | ||
| + | [[6. 4. 0. 0.] | ||
| + | [2. 0. 1. 4.] | ||
| + | [0. 7. 3. 4.] | ||
| + | [4. 0. 4. 0.]] | ||
| + | </div> | ||
| + | |||
| + | Mendefinisikan matrix di dalam python: | ||
| + | |||
| + | <div border-style: inset;"> | ||
| + | import numpy as np | ||
| + | <br>A = np.array([[6, 4, 0, 0], [2, 0 ,1, 4], [0, 7, 3, 4], [ 4, 0, 4, 0]], float) | ||
| + | B = np.array([50, 50, 0, 0], float) | ||
| + | <br>n = len(A) | ||
| + | </div> | ||
| + | |||
| + | Eliminasi Gauss | ||
| + | |||
| + | <div border-style: inset;"> | ||
| + | for k in range(0,n-1): | ||
| + | for i in range(k+1,n): | ||
| + | if A[i,k]!=0 : | ||
| + | lam = A[i,k]/A[k,k] | ||
| + | A[i,k:n] = A[i,k:n]-(A[k,k:n]*lam) | ||
| + | B[i] = B[i]-(B[k]*lam) | ||
| + | x = np.zeros(n,float) | ||
| + | for m in range(n-1,-1,-1): | ||
| + | x[m]=(B[m]-np.dot(A[m,m+1:n],x[m+1:n]))/A[m,m] | ||
| + | </div> | ||
| + | |||
==UTS== | ==UTS== | ||
untuk soal B | untuk soal B | ||
[[file:UTS_3b.JPG]] | [[file:UTS_3b.JPG]] | ||
Revision as of 15:08, 21 October 2019
Contents
Biodata
Nama : Mohammad Varian
NPM : 1606907713
Departemen : Teknik Mesin
Program Studi : Teknik Mesin
Biografi
nama saya adalah Mohamamd Varian, kelahiran Bekasi, 15 Agustus 1998. mengawali pendidikan di SDI Darussalam, lalu melanjutkan sekolah ke SMPN 12 Bekasi dan SMAN 2 Bekasi. Saat ini sedang menjalani perkuliahan di Departemen Teknik Mesin Universitas Indonesia.
Tugas 02
coding dari tugas 01 metode numerik
Tugas 03
Menggunakan persamaan matriks untuk eliminasi Gauss.
6x1 + 4x2 = 50 2x1 + x3 + 4x4 = 50 7x2 + 3x3 + 4x4 = 50 4x1 + 4x3 = 50
Didapat hasil matrix:
[[6. 4. 0. 0.] [2. 0. 1. 4.] [0. 7. 3. 4.] [4. 0. 4. 0.]]
Mendefinisikan matrix di dalam python:
import numpy as np
A = np.array([[6, 4, 0, 0], [2, 0 ,1, 4], [0, 7, 3, 4], [ 4, 0, 4, 0]], float) B = np.array([50, 50, 0, 0], float)
n = len(A)
Eliminasi Gauss
for k in range(0,n-1):
for i in range(k+1,n):
if A[i,k]!=0 :
lam = A[i,k]/A[k,k]
A[i,k:n] = A[i,k:n]-(A[k,k:n]*lam)
B[i] = B[i]-(B[k]*lam)
x = np.zeros(n,float)
for m in range(n-1,-1,-1):
x[m]=(B[m]-np.dot(A[m,m+1:n],x[m+1:n]))/A[m,m]
UTS
untuk soal B
