Difference between revisions of "Final Report of Hydrogen Storage Optimization Project, Darell Jeremia Sitompul, 6 Juni 2023"
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r_max = 20 | r_max = 20 | ||
a = np.zeros((r_max, 2)) | a = np.zeros((r_max, 2)) | ||
| − | for r in range (1, r_max + 1): | + | for r in range (1, r_max + 1): |
| − | + | flat_tube_height = (1000-((4*np.pi*r**3)/3))/(np.pi*(r)**2) | |
| − | + | sur_area = ((2*np.pi*r) * flat_tube_height) + ((2*np.pi*r**2)*2) | |
| − | + | a[r-1][0] = int(r) | |
| − | + | a[r-1][1] = np.round(sur_area, 5) | |
| − | + | print(": ", a[r-1][0], " "*(6 - len(str(a[r-1][0]))), | |
| − | + | " : ", a[r-1][1], " "*(12 - len(str(a[r-1][1]))), " :") | |
| − | + | ||
| − | for i in range(len(a)): | + | for i in range(len(a)): |
| − | + | for j in range (len(a)): | |
| − | + | if a[i][1] < a[j][1]: | |
| − | + | for n in range (2): | |
| − | + | temp = a[i][n] | |
| − | + | a[i][n] = a[j][n] | |
| − | + | a[j][n] = temp | |
| − | + | ||
| − | print("Minimum surface area will be found when") | + | print("Minimum surface area will be found when") |
| − | print("Radius = ", a[0][0]) | + | print("Radius = ", a[0][0]) |
| − | print("Surface Area : ", a[0][1]) | + | print("Surface Area : ", a[0][1]) |
Revision as of 23:56, 8 June 2023
Requirement:
- Capacity = 1 Liter - Budget = Rp.500.000,00 (Lima ratus ribu rupiah)
DRAFT PROGRAM
import numpy as np
print(": Radius : Surface Area :")
r_max = 20
a = np.zeros((r_max, 2))
for r in range (1, r_max + 1):
flat_tube_height = (1000-((4*np.pi*r**3)/3))/(np.pi*(r)**2)
sur_area = ((2*np.pi*r) * flat_tube_height) + ((2*np.pi*r**2)*2)
a[r-1][0] = int(r)
a[r-1][1] = np.round(sur_area, 5)
print(": ", a[r-1][0], " "*(6 - len(str(a[r-1][0]))),
" : ", a[r-1][1], " "*(12 - len(str(a[r-1][1]))), " :")
for i in range(len(a)):
for j in range (len(a)):
if a[i][1] < a[j][1]:
for n in range (2):
temp = a[i][n]
a[i][n] = a[j][n]
a[j][n] = temp
print("Minimum surface area will be found when")
print("Radius = ", a[0][0])
print("Surface Area : ", a[0][1])
