Difference between revisions of "Cyclone"
Agus.nuryadi (talk | contribs) |
Agus.nuryadi (talk | contribs) (→calculation Cyclone) |
||
Line 35: | Line 35: | ||
[[File:rumusG.jpg|5000px|thumb|centre|alt text]] | [[File:rumusG.jpg|5000px|thumb|centre|alt text]] | ||
− | from below graph, we can find d50 is 14 Micron Meter | + | from the below graph, we can find d50 is 14 Micron Meter |
[[File:rumusB.jpg|5000px|thumb|centre|alt text]] | [[File:rumusB.jpg|5000px|thumb|centre|alt text]] | ||
Line 46: | Line 46: | ||
− | + | we can find '''D'''c using below graph, and '''D'''c is '''16 cm''' | |
[[File:rumusC.jpg|5000px|thumb|centre|alt text]] | [[File:rumusC.jpg|5000px|thumb|centre|alt text]] | ||
− | |||
− | |||
− |
Revision as of 18:46, 25 November 2020
basic calculation cyclone
The nomographs by Zanker can be used to make a preliminary estimate of the size of cyclone needed. The specialist manufacturers of hydrocyclone equipment should be consulted to determine the best arrangements and design for a particular application. Zanker’s method is outlined below and illustrated in the Example below and based on an empirical equation by Bradley (1960):
Where:
d50 = the particle diameter for which the cyclone is 50 per cent efficient, Micron
Dc = diameter of the cyclone chamber, cm,
u = liquid viscosity, centipoise (mN s/m2),
L = feed flow rate, l/min,
pl = density of the liquid, g/cm3,
ps = density of the solid, g/cm3.
for calculating efficiency cyclone, we can find by below equation.
calculation Cyclone
Estimate the size of hydrocyclone needed to separate 90 percent of particles with a diameter greater than 20-micron m, from 10 m3/h of a dilute slurry.
Physical properties: solid density 2000 kg/m3, liquid density 1000 kg/m3, viscosity 1 mN s/m
So we can find:
from the below graph, we can find d50 is 14 Micron Meter
Determination of d50 from the desired particle separation
for
we can find Dc using below graph, and Dc is 16 cm