Difference between revisions of "Final Report of Hydrogen Storage Optimization Project, Darell Jeremia Sitompul, 6 Juni 2023"
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DRAFT PROGRAM | DRAFT PROGRAM | ||
+ | Finding Smallest Surface Area of the capsule with radius from 0 to 20 centimeters | ||
import numpy as np | import numpy as np |
Revision as of 23:58, 8 June 2023
Requirement:
- Capacity = 1 Liter - Budget = Rp.500.000,00 (Lima ratus ribu rupiah)
DRAFT PROGRAM
Finding Smallest Surface Area of the capsule with radius from 0 to 20 centimeters
import numpy as np print(": Radius : Surface Area :") r_max = 20 a = np.zeros((r_max, 2)) for r in range (1, r_max + 1): flat_tube_height = (1000-((4*np.pi*r**3)/3))/(np.pi*(r)**2) sur_area = ((2*np.pi*r) * flat_tube_height) + ((2*np.pi*r**2)*2) a[r-1][0] = int(r) a[r-1][1] = np.round(sur_area, 5) print(": ", a[r-1][0], " "*(6 - len(str(a[r-1][0]))), " : ", a[r-1][1], " "*(12 - len(str(a[r-1][1]))), " :") for i in range(len(a)): for j in range (len(a)): if a[i][1] < a[j][1]: for n in range (2): temp = a[i][n] a[i][n] = a[j][n] a[j][n] = temp print("Minimum surface area will be found when") print("Radius = ", a[0][0]) print("Surface Area : ", a[0][1])