Difference between revisions of "Talk:Farhan Syahputra Derajat"
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Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 14:05:16) [MSC v.1915 32 bit (Intel)] on win32 | Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 14:05:16) [MSC v.1915 32 bit (Intel)] on win32 | ||
Type "help", "copyright", "credits" or "license()" for more information. | Type "help", "copyright", "credits" or "license()" for more information. |
Latest revision as of 13:33, 20 February 2019
metode numerik
Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 14:05:16) [MSC v.1915 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license()" for more information. >>> print ('TUGAS METNUM') print ('misalkan terdapat persamaan linier dua variable \n ax+by=c \n px+qy=r') a= float(input('nilai a=')) b= float(input('nilai b=')) c= float(input('nilai c=')) p= float(input('nilai p=')) q= float(input('nilai q=')) r= float(input('nilai r='))
if a==p:
k=b-q j=c-r y=j/k x=(c-(b*y))/a print ('nilai x',x,'nilai y',y)
elif a==0:
y=c/b x=(r-(q*y))/p print('nilai x', x, 'nilai y', y)
elif b==0:
x=c/a y=(r-(p*x))/q print('nilai x', x, 'nilai y', y)
elif p==0:
y=r/q x=(c-(b*y))/a print('nilai x', x, 'nilai y', y)
elif q==0:
x=r/q y=(c-(a*x))/b print('nilai x', x, 'nilai y', y)
elif a!=p:
s=(a*p) t=(b*p) u=(c*p) ss=(p*a) tt=(q*a) uu=(r*a) x=(u-uu)/(t-tt) y=(c-(a*x))/b print('nilai x=', x, 'nilai y=', y) input()