Difference between revisions of "Talk:Farhan Syahputra Derajat"

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== metode numerik ==
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Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 14:05:16) [MSC v.1915 32 bit (Intel)] on win32
 
Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 14:05:16) [MSC v.1915 32 bit (Intel)] on win32
 
Type "help", "copyright", "credits" or "license()" for more information.
 
Type "help", "copyright", "credits" or "license()" for more information.

Latest revision as of 13:33, 20 February 2019

metode numerik

Python 3.7.1 (v3.7.1:260ec2c36a, Oct 20 2018, 14:05:16) [MSC v.1915 32 bit (Intel)] on win32 Type "help", "copyright", "credits" or "license()" for more information. >>> print ('TUGAS METNUM') print ('misalkan terdapat persamaan linier dua variable \n ax+by=c \n px+qy=r') a= float(input('nilai a=')) b= float(input('nilai b=')) c= float(input('nilai c=')) p= float(input('nilai p=')) q= float(input('nilai q=')) r= float(input('nilai r='))

if a==p:

   k=b-q
   j=c-r
   y=j/k
   x=(c-(b*y))/a
   print ('nilai x',x,'nilai y',y)

elif a==0:

   y=c/b
   x=(r-(q*y))/p
   print('nilai x', x, 'nilai y', y)

elif b==0:

   x=c/a
   y=(r-(p*x))/q
   print('nilai x', x, 'nilai y', y)

elif p==0:

   y=r/q
   x=(c-(b*y))/a
   print('nilai x', x, 'nilai y', y)

elif q==0:

   x=r/q
   y=(c-(a*x))/b
   print('nilai x', x, 'nilai y', y)

elif a!=p:

   s=(a*p)
   t=(b*p)
   u=(c*p)
   ss=(p*a)
   tt=(q*a)
   uu=(r*a)
   x=(u-uu)/(t-tt)
   y=(c-(a*x))/b
   print('nilai x=', x, 'nilai y=', y)
   input()