Difference between revisions of "Contoh soal terkait manometer menggunakan ChatGPT"

From ccitonlinewiki
Jump to: navigation, search
 
Line 9: Line 9:
 
     the mercury in the manometer.
 
     the mercury in the manometer.
  
We can rearrange the equation to solve for h:
+
    We can rearrange the equation to solve for h:
 
+
    h = ΔP / (ρg)
h = ΔP / (ρg)
+
    The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
 
+
    Substituting the values, we get:
The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
+
    h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
 
+
    h = 0.183 meters or 18.3 cm
Substituting the values, we get:
+
    Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.
 
 
h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
 
 
 
h = 0.183 meters or 18.3 cm
 
 
 
Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.
 

Latest revision as of 17:20, 28 February 2023

An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?


  = To find the difference in height of the mercury in the manometer, we need to know the 
    pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
    and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
    where ΔP is the pressure difference between the two sides of the U tube, ρ is the density 
    of the mercury, g is the acceleration due to gravity, and h is the difference in height of 
    the mercury in the manometer.
    We can rearrange the equation to solve for h:
    h = ΔP / (ρg)
    The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
    Substituting the values, we get:
    h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
    h = 0.183 meters or 18.3 cm
    Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.