Difference between revisions of "Contoh soal terkait manometer menggunakan ChatGPT"
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= To find the difference in height of the mercury in the manometer, we need to know the | = To find the difference in height of the mercury in the manometer, we need to know the | ||
pressure on the other side of the U tube. Assuming the other side is open to the atmosphere | pressure on the other side of the U tube. Assuming the other side is open to the atmosphere | ||
− | and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: | + | and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh |
− | + | where ΔP is the pressure difference between the two sides of the U tube, ρ is the density | |
+ | of the mercury, g is the acceleration due to gravity, and h is the difference in height of | ||
+ | the mercury in the manometer. | ||
− | + | We can rearrange the equation to solve for h: | |
− | + | h = ΔP / (ρg) | |
− | We can rearrange the equation to solve for h: | + | The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s². |
− | + | Substituting the values, we get: | |
− | h = ΔP / (ρg) | + | h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²) |
− | + | h = 0.183 meters or 18.3 cm | |
− | The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s². | + | Therefore, the difference in the height of the mercury in the manometer is 18.3 cm. |
− | |||
− | Substituting the values, we get: | ||
− | |||
− | h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²) | ||
− | |||
− | h = 0.183 meters or 18.3 cm | ||
− | |||
− | Therefore, the difference in the height of the mercury in the manometer is 18.3 cm. |
Latest revision as of 17:20, 28 February 2023
An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?
= To find the difference in height of the mercury in the manometer, we need to know the pressure on the other side of the U tube. Assuming the other side is open to the atmosphere and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh where ΔP is the pressure difference between the two sides of the U tube, ρ is the density of the mercury, g is the acceleration due to gravity, and h is the difference in height of the mercury in the manometer.
We can rearrange the equation to solve for h: h = ΔP / (ρg) The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s². Substituting the values, we get: h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²) h = 0.183 meters or 18.3 cm Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.