Difference between revisions of "Contoh soal terkait manometer menggunakan ChatGPT"
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| − | = To find the difference in height of the mercury in the manometer, we need to know the pressure on the other side of the U | + | = To find the difference in height of the mercury in the manometer, we need to know the |
| − | + | pressure on the other side of the U tube. Assuming the other side is open to the atmosphere | |
| + | and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh | ||
| + | where ΔP is the pressure difference between the two sides of the U tube, ρ is the density | ||
| + | of the mercury, g is the acceleration due to gravity, and h is the difference in height of | ||
| + | the mercury in the manometer. | ||
| − | + | We can rearrange the equation to solve for h: | |
| − | + | h = ΔP / (ρg) | |
| − | + | The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s². | |
| − | + | Substituting the values, we get: | |
| − | We can rearrange the equation to solve for h: | + | h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²) |
| − | + | h = 0.183 meters or 18.3 cm | |
| − | h = ΔP / (ρg) | + | Therefore, the difference in the height of the mercury in the manometer is 18.3 cm. |
| − | |||
| − | The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s². | ||
| − | |||
| − | Substituting the values, we get: | ||
| − | |||
| − | h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²) | ||
| − | |||
| − | h = 0.183 meters or 18.3 cm | ||
| − | |||
| − | Therefore, the difference in the height of the mercury in the manometer is 18.3 cm. | ||
Latest revision as of 17:20, 28 February 2023
An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?
= To find the difference in height of the mercury in the manometer, we need to know the
pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
where ΔP is the pressure difference between the two sides of the U tube, ρ is the density
of the mercury, g is the acceleration due to gravity, and h is the difference in height of
the mercury in the manometer.
We can rearrange the equation to solve for h:
h = ΔP / (ρg)
The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
Substituting the values, we get:
h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
h = 0.183 meters or 18.3 cm
Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.
