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An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?
 
An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?
  
= To find the difference in height of the mercury in the manometer, we need to know the pressure on the other side of the U tube. Assuming the other side is open to the atmosphere and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation:
 
  
ΔP = ρgh
+
  = To find the difference in height of the mercury in the manometer, we need to know the
 +
    pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
 +
    and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
 +
    where ΔP is the pressure difference between the two sides of the U tube, ρ is the density
 +
    of the mercury, g is the acceleration due to gravity, and h is the difference in height of
 +
    the mercury in the manometer.
  
where ΔP is the pressure difference between the two sides of the U tube, ρ is the density of the mercury, g is the acceleration due to gravity, and h is the difference in height of the mercury in the manometer.
+
    We can rearrange the equation to solve for h:
 
+
    h = ΔP / (ρg)
We can rearrange the equation to solve for h:
+
    The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
 
+
    Substituting the values, we get:
h = ΔP / (ρg)
+
    h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
 
+
    h = 0.183 meters or 18.3 cm
The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
+
    Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.
 
 
Substituting the values, we get:
 
 
 
h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
 
 
 
h = 0.183 meters or 18.3 cm
 
 
 
Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.
 

Latest revision as of 17:20, 28 February 2023

An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?


  = To find the difference in height of the mercury in the manometer, we need to know the 
    pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
    and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
    where ΔP is the pressure difference between the two sides of the U tube, ρ is the density 
    of the mercury, g is the acceleration due to gravity, and h is the difference in height of 
    the mercury in the manometer.
    We can rearrange the equation to solve for h:
    h = ΔP / (ρg)
    The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
    Substituting the values, we get:
    h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
    h = 0.183 meters or 18.3 cm
    Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.