Difference between revisions of "Contoh soal terkait manometer menggunakan ChatGPT"

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     pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
 
     pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
 
     and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
 
     and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
 
 
     where ΔP is the pressure difference between the two sides of the U tube, ρ is the density  
 
     where ΔP is the pressure difference between the two sides of the U tube, ρ is the density  
 
     of the mercury, g is the acceleration due to gravity, and h is the difference in height of  
 
     of the mercury, g is the acceleration due to gravity, and h is the difference in height of  

Revision as of 17:19, 28 February 2023

An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?


  = To find the difference in height of the mercury in the manometer, we need to know the 
    pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
    and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
    where ΔP is the pressure difference between the two sides of the U tube, ρ is the density 
    of the mercury, g is the acceleration due to gravity, and h is the difference in height of 
    the mercury in the manometer.

We can rearrange the equation to solve for h:

h = ΔP / (ρg)

The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².

Substituting the values, we get:

h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)

h = 0.183 meters or 18.3 cm

Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.