Difference between revisions of "Contoh soal terkait manometer menggunakan ChatGPT"
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and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh | and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh | ||
| − | where ΔP is the pressure difference between the two sides of the U tube, ρ is the density of the mercury, g is the acceleration due to gravity, and h is the difference in height of the mercury in the manometer. | + | where ΔP is the pressure difference between the two sides of the U tube, ρ is the density |
| + | of the mercury, g is the acceleration due to gravity, and h is the difference in height of the mercury in the manometer. | ||
We can rearrange the equation to solve for h: | We can rearrange the equation to solve for h: | ||
Revision as of 17:18, 28 February 2023
An open manometer has a pressure of 100 cmHg on one side of a U tube. What is the difference in the height of the mercury in the manometer?
= To find the difference in height of the mercury in the manometer, we need to know the
pressure on the other side of the U tube. Assuming the other side is open to the atmosphere
and the atmospheric pressure is 760 mmHg or 76 cmHg, we can use the equation: ΔP = ρgh
where ΔP is the pressure difference between the two sides of the U tube, ρ is the density
of the mercury, g is the acceleration due to gravity, and h is the difference in height of the mercury in the manometer.
We can rearrange the equation to solve for h:
h = ΔP / (ρg)
The density of mercury is 13.6 g/cm³ and the acceleration due to gravity is 9.81 m/s².
Substituting the values, we get:
h = (100 cmHg - 76 cmHg) / (13.6 g/cm³ x 9.81 m/s²)
h = 0.183 meters or 18.3 cm
Therefore, the difference in the height of the mercury in the manometer is 18.3 cm.
